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3 MIN LESSON · SCIENCE

Motion: Distance, Displacement, Velocity, Acceleration and the Equations of Motion

Describe motion precisely using distance and displacement, speed and velocity, and acceleration; read distance–time and velocity–time graphs; and use the three equations of motion.

Describing motion

An object is in motion when its position changes with time, compared with a reference point. A tree is at rest relative to the ground but in motion relative to a passing train.

Distance and displacement

  • Distance is the total length of the path travelled. It has magnitude only, so it is a scalar.

  • Displacement is the shortest straight-line distance from the starting point to the final position, in a given direction. It has magnitude and direction, so it is a vector.

Example. You walk 4 m east and then 3 m north. The distance you covered is 4 + 3 = 7 m. Your displacement is √(4² + 3²) = 5 m, pointing north-east of the start.

If you walk round a circular track and come back to the start, the distance is the length of the track, but the displacement is zero.

Speed and velocity

Speed = distance ÷ time. Velocity = displacement ÷ time.

Both are measured in m/s. Speed is a scalar; velocity is a vector.

  • Uniform motion: equal distances are covered in equal intervals of time.

  • Average speed = total distance ÷ total time.

Example. A car covers 60 km in the first hour and 40 km in the next hour. Its average speed is (60 + 40) ÷ 2 = 50 km/h.

To convert km/h to m/s, multiply by 5/18. For example, 72 km/h = 72 × 5/18 = 20 m/s.

Acceleration

Acceleration is the rate of change of velocity:

a = (v − u) / t

Here u is the initial velocity, v the final velocity and t the time taken. The unit is m/s².

  • If the velocity increases, the acceleration is positive.

  • If the velocity decreases, the acceleration is negative. This is called retardation or deceleration.

Example. A bus speeds up from rest to 10 m/s in 5 s. Its acceleration is (10 − 0) ÷ 5 = 2 m/s².

Graphs of motion

Distance–time graph

  • A straight sloping line means uniform speed. The slope of the line gives the speed.

  • A line parallel to the time axis means the object is at rest.

  • A curved line means non-uniform speed.

Velocity–time graph

  • A horizontal line means constant velocity (zero acceleration).

  • A straight sloping line means uniform acceleration. The slope gives the acceleration.

  • The area under the graph gives the displacement.

The equations of motion

For motion in a straight line with uniform acceleration:

First equation: v = u + at

Second equation: s = ut + ½at²

Third equation: v² = u² + 2as

where s is the displacement.

Example. A car travelling at 20 m/s brakes uniformly and stops in 4 s. Find the acceleration and the stopping distance.

  • a = (0 − 20) ÷ 4 = −5 m/s²

  • Using v² = u² + 2as: 0 = 400 + 2(−5)s, so s = 40 m.

Uniform circular motion

An object moving in a circle at constant speed is still accelerating, because the direction of its velocity keeps changing. This is called uniform circular motion. Examples include the tip of a clock's hand, an athlete running round a circular track at steady speed, and (approximately) the Moon going round the Earth.

For an object of speed v moving once round a circle of radius r in time t:

v = 2πr / t

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