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4 MIN LESSON · QUANTITATIVE APTITUDE

Time, Speed and Distance: Trains, Boats and Relative Speed

Speed = distance ÷ time, unit conversion in one step, relative speed for trains and chases, and upstream–downstream boat problems, with the standard exam shortcuts.

The core relation

Distance = speed × time. Keep units consistent.

To convert km/h to m/s, multiply by 5/18. To convert m/s to km/h, multiply by 18/5.

72 km/h × 5/18 = 20 m/s. 54 km/h = 15 m/s. 90 km/h = 25 m/s.

Trains

A train crossing something must cover its own length plus the length of what it crosses.

Crossing

Distance covered

a pole, a person or a signal

length of the train

a platform, bridge or tunnel

train + platform

another train

sum of both lengths

Example. A 200 m train at 72 km/h (20 m/s) crosses a 300 m platform in 500 ÷ 20 = 25 seconds.

Relative speed

  • Moving in opposite directions: add the speeds.

  • Moving in the same direction: subtract them.

Example. Trains of 120 m and 180 m run towards each other at 50 and 40 km/h. Relative speed = 90 km/h = 25 m/s, so they pass in 300 ÷ 25 = 12 s.

Chases. A thief with a 200 m head start runs at 10 km/h, chased at 12 km/h. The gap closes at 2 km/h = 2000 m per hour, so it takes 0.1 h = 6 minutes.

Meeting. Two people 90 km apart walking towards each other at 20 and 25 km/h meet after 90 ÷ 45 = 2 hours.

Boats and streams

With boat speed b in still water and stream speed s:

  • downstream speed = b + s

  • upstream speed = b − s

  • b = (downstream + upstream) / 2 and s = (downstream − upstream) / 2

Example. Downstream 20 km/h and upstream 12 km/h give b = 16 and s = 4 km/h.

Late and early

At a fraction k of the usual speed, the time becomes 1/k of the usual time.

Example. Walking at 4/5 of the usual speed makes someone 10 minutes late. The time is 5/4 of usual, so a quarter of the usual time is 10 minutes and the usual time is 40 minutes.

Average speed

For equal distances at a and b km/h: 2ab/(a + b). Otherwise: total distance ÷ total time.

Shortcuts and tricks

The standard way is distance = speed × time with units converted first. These shortcuts handle the common patterns directly.

km/h to m/s

Example: 90 km/h in m/s.

  • Standard way: 90 × 1000 ÷ 3600 = 25 m/s.

  • Shortcut: multiply by 5/18, or divide by 3.6: 90 ÷ 3.6 = 25 m/s.

Speed and time move in opposite ratios

Example: at 3/4 of the usual speed, a person is 20 minutes late. Find the usual time.

  • Standard way: let the usual time be t. The new time is 4t/3, so 4t/3 − t = 20 and t = 60 minutes.

  • Shortcut: speed × 3/4 means time × 4/3. The extra 1/3 of the usual time is 20 minutes, so the usual time is 60 minutes.

Boats: half the sum and half the difference

Example: downstream 14 km/h, upstream 8 km/h.

  • Standard way: b + s = 14 and b − s = 8, so b = 11 and s = 3.

  • Shortcut: boat = (14 + 8)/2 = 11 km/h, stream = (14 − 8)/2 = 3 km/h.

Two speeds over the same distance

Example: at 40 km/h a trip takes 30 minutes longer than at 50 km/h. Find the distance.

  • Standard way: d/40 − d/50 = 1/2, so d/200 = 1/2 and d = 100 km.

  • Shortcut: d = (product of speeds × time difference) ÷ speed difference = 40 × 50 × ½ ÷ 10 = 100 km.

Exam tips

  • Convert units before anything else.

  • Draw a quick line diagram for meeting and overtaking problems.

  • Time and speed are inversely proportional for a fixed distance.

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